What is the solution for (dy)/(dt)=0.125(y-3) ?

The solution for (dy)/(dt)=0.125(y-3) is y=e^{0.125t+c_{1}}+3

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(dy)/(dt)=0.125(y-3)

\frac{d y}{d t} = 0.125 (y - 3)

y = e^{0.125 t + c_{1}} + 3

Solution steps

\frac{d y}{d t} = 0.125 (y - 3)

Solve separable ODE:

y = e^{0.125 t + c_{1}} + 3

y = e^{0.125 t + c_{1}} + 3

y^{^{'}} = y, y (0) = 1

\frac{d x}{d y} + 4 x y = x

y^{^{'}} + \frac{4 x}{x ^{2} + 2} y = 0

\frac{d y}{d x} = \frac{( 1 - x ^{2} )}{y ^{2}}

\frac{d y}{d t} + 20 y = 24, y (0) = 0

What is the solution for (dy)/(dt)=0.125(y-3) ?
The solution for (dy)/(dt)=0.125(y-3) is y=e^{0.125t+c_{1}}+3