What is the solution for xy^'+y=41sqrt(x) ?

The solution for xy^'+y=41sqrt(x) is y=(82x^{1/2})/3+(c_{1})/x

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xy^'+y=41sqrt(x)

x y^{^{'}} + y = 41 x

y = \frac{82 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = 41 x

Solve linear ODE:

y = \frac{82 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

y = \frac{82 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

f (x) = sin^{2} (x)

\frac{d}{d x} (2 e^{x} cos (2 x))

2 - X^{2}, - X = Y

\frac{d}{d x} (x y + y)

f (x) = \frac{c ^{8} - x ^{8}}{c ^{8} + x ^{8}}

What is the solution for xy^'+y=41sqrt(x) ?
The solution for xy^'+y=41sqrt(x) is y=(82x^{1/2})/3+(c_{1})/x