en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=y+5

Solution

y^{^{'}} = y + 5

Solution

y = e^{t + c_{1}} - 5

Solution steps

y^{'} (t) = y + 5

Solve separable ODE:

y = e^{t + c_{1}} - 5

y = e^{t + c_{1}} - 5

Graph

Popular Examples

(xln(x^2))y^'=2y

(x ln (x^{2})) y^{^{'}} = 2 y

(dy)/(dt)+0.5ty=4t

\frac{d y}{d t} + 0.5 t y = 4 t

(dy}{dx}=\frac{y^2)/x ,y(e)=3

\frac{d y}{d x} = \frac{y ^{2}}{x}, y (e) = 3

1/y dy=(-x)/(sqrt(1+x^2))dx

\frac{1}{y} d y = \frac{- x}{1 + x ^{2}} d x

x^{^{'}} = 1 - 3 x + 2 x^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=y+5 ?
The solution for y^'=y+5 is y=e^{t+c_{1}}-5