What is the solution for xe^{(x^2)}+yy^'=0 ?

The solution for xe^{(x^2)}+yy^'=0 is y=sqrt(-e^{x^2)+c_{1}},y=-sqrt(-e^{x^2)+c_{1}}

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xe^{(x^2)}+yy^'=0

x e^{(x^{2})} + y y^{^{'}} = 0

y = - e^{x^{2}} + c_{1}, y = - - e^{x^{2}} + c_{1}

Solution steps

x e^{(x^{2})} + y y^{'} (x) = 0

Solve separable ODE:

y = - e^{x^{2}} + c_{1}, y = - - e^{x^{2}} + c_{1}

y = - e^{x^{2}} + c_{1}, y = - - e^{x^{2}} + c_{1}

y^{^{'}} = e^{- 5 y} (2 7 x - 4), y (0) = 1

y^{^{'}} = \frac{y ^{2} + 3}{( 2 x y )}

e^{2 x} \frac{d y}{d x} = \frac{2}{y}

ln (x) y^{^{'}} - (\frac{2 \cdot y}{x}) = 0

\frac{d x}{d y} = sin (5 x)

What is the solution for xe^{(x^2)}+yy^'=0 ?
The solution for xe^{(x^2)}+yy^'=0 is y=sqrt(-e^{x^2)+c_{1}},y=-sqrt(-e^{x^2)+c_{1}}