What is the solution for (dy)/(dx)=-4/7 x^3y^3 ?

The solution for (dy)/(dx)=-4/7 x^3y^3 is y=sqrt(-7/(2(-x^4+c_{1)))},y=-sqrt(-7/(2(-x^4+c_{1)))}

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(dy)/(dx)=-4/7 x^3y^3

\frac{d y}{d x} = - \frac{4}{7} x^{3} y^{3}

y = - \frac{7}{2 ( - x ^{4} + c _{1} )}, y = - - \frac{7}{2 ( - x ^{4} + c _{1} )}

Solution steps

\frac{d y}{d x} = - \frac{4}{7} x^{3} y^{3}

Solve separable ODE:

y = - \frac{7}{2 ( - x ^{4} + c _{1} )}, y = - - \frac{7}{2 ( - x ^{4} + c _{1} )}

y = - \frac{7}{2 ( - x ^{4} + c _{1} )}, y = - - \frac{7}{2 ( - x ^{4} + c _{1} )}

\frac{d x}{d y} - \frac{1}{y} = \frac{2 x}{2 y}, y (1) = 2

\frac{d y}{d x} = \frac{- 2 x y}{x ^{2} + 1}

a (x d y + 2 y d x) = x y d x

y^{^{'}} = y x

\frac{d y}{d x} y = 1

What is the solution for (dy)/(dx)=-4/7 x^3y^3 ?
The solution for (dy)/(dx)=-4/7 x^3y^3 is y=sqrt(-7/(2(-x^4+c_{1)))},y=-sqrt(-7/(2(-x^4+c_{1)))}