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Popular >

(yy^')/x+e^y=0

Solution

\frac{y y ^{^{'}}}{x} + e^{y} = 0

Solution

y = - W (\frac{- x ^{2} + c _{1}}{2 e}) - 1

Solution steps

\frac{y y ^{'} ( x )}{x} + e^{y} = 0

Solve separable ODE:

y = - W (\frac{- x ^{2} + c _{1}}{2 e}) - 1

y = - W (\frac{- x ^{2} + c _{1}}{2 e}) - 1

Popular Examples

e^{-(x^2+y^2)}(xdx+ydy)=0

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x^{2} y d y - e^{y} d x = 0

y^'=(y+3)/(7t+50),y(2)=0

y^{^{'}} = \frac{y + 3}{7 t + 50}, y (2) = 0

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(2 x - 8 x y) d x - (x^{2} + 4) d y = 0

y/x (dy)/(dx)=sqrt((1+x^2)(1+y^2))

\frac{y}{x} \frac{d y}{d x} = (1 + x^{2}) (1 + y^{2})

Frequently Asked Questions (FAQ)

What is the solution for (yy^')/x+e^y=0 ?
The solution for (yy^')/x+e^y=0 is y=-\W((-x^2+c_{1})/(2e))-1