What is the solution for y^'=(y+3)/(7t+50),y(2)=0 ?

The solution for y^'=(y+3)/(7t+50),y(2)=0 is y=(3\sqrt[7]{7t+50}}{e^{\frac{6ln(2))/7}}-3

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y^'=(y+3)/(7t+50),y(2)=0

y^{^{'}} = \frac{y + 3}{7 t + 50}, y (2) = 0

y = \frac{3 7 7 t + 50}{e ^{\frac{6 l n ( 2 )}{7}}} - 3

Solution steps

y^{'} (t) = \frac{y + 3}{7 t + 50}

Solve separable ODE:

y = \frac{3 7 7 t + 50}{e ^{\frac{6 l n ( 2 )}{7}}} - 3

y = \frac{3 7 7 t + 50}{e ^{\frac{6 l n ( 2 )}{7}}} - 3

(2 x - 8 x y) d x - (x^{2} + 4) d y = 0

\frac{y}{x} \frac{d y}{d x} = (1 + x^{2}) (1 + y^{2})

y - x y^{^{'}} = 1 + x^{2} y^{^{'}}

(x^{2} + 1) y^{3} + x^{2} \cdot \frac{d y}{d x} = 0

x \frac{d y}{d x} - y ln (y) = 0

What is the solution for y^'=(y+3)/(7t+50),y(2)=0 ?
The solution for y^'=(y+3)/(7t+50),y(2)=0 is y=(3\sqrt[7]{7t+50}}{e^{\frac{6ln(2))/7}}-3