What is the solution for (dy)/(dx)=((x+2))/(2y),y(0)=1 ?

The solution for (dy)/(dx)=((x+2))/(2y),y(0)=1 is y=sqrt((x^2)/2+2x+1)

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(dy)/(dx)=((x+2))/(2y),y(0)=1

\frac{d y}{d x} = \frac{( x + 2 )}{2 y}, y (0) = 1

y = \frac{x ^{2}}{2} + 2 x + 1

Solution steps

\frac{d y}{d x} = \frac{( x + 2 )}{2 y}

Solve separable ODE:

y = \frac{x ^{2}}{2} + 2 x + 1

y = \frac{x ^{2}}{2} + 2 x + 1

a y^{^{'}} + b y = c

\frac{d x}{d t} = 18 - \frac{9 x}{10}

u^{^{'}} = (\frac{H ( t )}{t})^{\frac{1}{3}}

4 x^{2} + 2 x^{2} d x - 4 y \cdot d y = 8 x \cdot d x

(ln (y))^{5} \frac{d y}{d x} = x^{5} y, y (1) = e^{2}

What is the solution for (dy)/(dx)=((x+2))/(2y),y(0)=1 ?
The solution for (dy)/(dx)=((x+2))/(2y),y(0)=1 is y=sqrt((x^2)/2+2x+1)