What is the solution for (dx)/(dt)=18-(9x)/(10) ?

The solution for (dx)/(dt)=18-(9x)/(10) is x=-(e^{(-9t-c_{1})/(10)})/9+20

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(dx)/(dt)=18-(9x)/(10)

\frac{d x}{d t} = 18 - \frac{9 x}{10}

x = - \frac{e ^{\frac{- 9 t - c _{1}}{10}}}{9} + 20

Solution steps

\frac{d x}{d t} = 18 - \frac{9 x}{10}

Solve separable ODE:

x = - \frac{e ^{\frac{- 9 t - c _{1}}{10}}}{9} + 20

x = - \frac{e ^{\frac{- 9 t - c _{1}}{10}}}{9} + 20

u^{^{'}} = (\frac{H ( t )}{t})^{\frac{1}{3}}

4 x^{2} + 2 x^{2} d x - 4 y \cdot d y = 8 x \cdot d x

(ln (y))^{5} \frac{d y}{d x} = x^{5} y, y (1) = e^{2}

y^{^{'}} = (1 - 11 x) y^{2}, y (0) = - \frac{1}{9}

x y (y + 2) d x - (y + 1) d y = 0

What is the solution for (dx)/(dt)=18-(9x)/(10) ?
The solution for (dx)/(dt)=18-(9x)/(10) is x=-(e^{(-9t-c_{1})/(10)})/9+20