What is the solution for (dy)/(dx)=-5/3 x^3y^6 ?

The solution for (dy)/(dx)=-5/3 x^3y^6 is y=-\sqrt[5]{(12)/(5(-5x^4+c_{1))}}

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(dy)/(dx)=-5/3 x^3y^6

\frac{d y}{d x} = - \frac{5}{3} x^{3} y^{6}

y = - 5 \frac{12}{5 ( - 5 x ^{4} + c _{1} )}

Solution steps

\frac{d y}{d x} = - \frac{5}{3} x^{3} y^{6}

Solve separable ODE:

y = - 5 \frac{12}{5 ( - 5 x ^{4} + c _{1} )}

y = - 5 \frac{12}{5 ( - 5 x ^{4} + c _{1} )}

\frac{d x}{d y} = y - 4 x y

\frac{d y}{d t} + 2 (t + 1) y^{2} = 0, y (0) = - \frac{1}{15}

10 y^{^{'}} - 2 y - 63 = 9 y^{^{'}}

y^{5} \frac{d y}{d x} = 4 x^{4} y^{6} - 12 x^{4}

y^{^{'}} + tan (4 \cdot x) y = 0

What is the solution for (dy)/(dx)=-5/3 x^3y^6 ?
The solution for (dy)/(dx)=-5/3 x^3y^6 is y=-\sqrt[5]{(12)/(5(-5x^4+c_{1))}}