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Popular >

10y^'-2y-63=9y^'

Solution

10 y^{^{'}} - 2 y - 63 = 9 y^{^{'}}

Solution

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{63}{2}

Solution steps

10 y^{'} (t) - 2 y - 63 = 9 y^{'} (t)

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{63}{2}

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{63}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for 10y^'-2y-63=9y^' ?
The solution for 10y^'-2y-63=9y^' is y=(e^{2t+c_{1}})/2-63/2