What is the solution for 2xy+8x+(x^2-4)(dy)/(dx)=0 ?

The solution for 2xy+8x+(x^2-4)(dy)/(dx)=0 is y=(c_{1})/(x^2-4)-4

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2xy+8x+(x^2-4)(dy)/(dx)=0

2 x y + 8 x + (x^{2} - 4) \frac{d y}{d x} = 0

y = \frac{c _{1}}{x ^{2} - 4} - 4

Solution steps

2 x y + 8 x + (x^{2} - 4) \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 4} - 4

y = \frac{c _{1}}{x ^{2} - 4} - 4

\frac{2 v + 1}{v - 3 v ^{2}} d v = \frac{1}{x} d x

y^{^{'}} sec (t) = - \frac{y ^{3}}{2}

\frac{d}{d x} (θ (x)) = sin (θ (x)) \cdot cos (θ (x))

3 x^{2} y^{5} d x + 5 x^{3} y^{4} d y = 0

(1 + cos (x)) d y = y \cdot sin (x) d x

What is the solution for 2xy+8x+(x^2-4)(dy)/(dx)=0 ?
The solution for 2xy+8x+(x^2-4)(dy)/(dx)=0 is y=(c_{1})/(x^2-4)-4