What is the solution for 3x^2y^5dx+5x^3y^4dy=0 ?

The solution for 3x^2y^5dx+5x^3y^4dy=0 is y=(c_{1})/(x^{3/5)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2y^5dx+5x^3y^4dy=0

3 x^{2} y^{5} d x + 5 x^{3} y^{4} d y = 0

y = \frac{c _{1}}{x ^{\frac{3}{5}}}

Solution steps

3 x^{2} y^{5} d x + 5 x^{3} y^{4} d y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{\frac{3}{5}}}

y = \frac{c _{1}}{x ^{\frac{3}{5}}}

(1 + cos (x)) d y = y \cdot sin (x) d x

(y - 2) \frac{d y}{d x} = 3 x - 5

x \frac{d y}{d x} - 3 y = - 3

\frac{d h}{d t} = - h^{4}

\frac{d y}{d x} = \frac{y cos ( x )}{7 + y ^{2}}, y (0) = 1

What is the solution for 3x^2y^5dx+5x^3y^4dy=0 ?
The solution for 3x^2y^5dx+5x^3y^4dy=0 is y=(c_{1})/(x^{3/5)}