What is the solution for ((dy)/(dx))+y=yx(e^{(x+2)}) ?

The solution for ((dy)/(dx))+y=yx(e^{(x+2)}) is y=e^{e^2(e^xx-e^x)-x+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((dy)/(dx))+y=yx(e^{(x+2)})

(\frac{d y}{d x}) + y = y x (e^{(x + 2)})

y = e^{e^{2} (e^{x} x - e^{x}) - x + c_{1}}

Solution steps

(\frac{d y}{d x}) + y = y x (e^{(x + 2)})

Solve separable ODE:

y = e^{e^{2} (e^{x} x - e^{x}) - x + c_{1}}

y = e^{e^{2} (e^{x} x - e^{x}) - x + c_{1}}

\frac{d y}{d x} = \frac{e ^{7 x + y}}{y - 4}

\frac{d P}{d t} = \frac{1}{20} (1 - \frac{P}{1000})

(x + 1) y y^{^{'}} = y^{2} + 1, y (1) = 3

x y^{^{'}} = e^{8 y + x}

y = 1 + y^{^{'}}

What is the solution for ((dy)/(dx))+y=yx(e^{(x+2)}) ?
The solution for ((dy)/(dx))+y=yx(e^{(x+2)}) is y=e^{e^2(e^xx-e^x)-x+c_{1}}