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Popular >

x^2y^'=1+y,y(1)=3

Solution

x^{2} y^{^{'}} = 1 + y, y (1) = 3

Solution

y = 4 e^{- \frac{1}{x} + 1} - 1

Solution steps

x^{2} y^{'} (x) = 1 + y

Solve separable ODE:

y = 4 e^{- \frac{1}{x} + 1} - 1

y = 4 e^{- \frac{1}{x} + 1} - 1

Popular Examples

(dy)/(dx)=(-2-1.2y)/(0.5+1.2x)

\frac{d y}{d x} = \frac{- 2 - 1.2 y}{0.5 + 1.2 x}

t^{2} y^{^{'}} + 5 t^{2} y = 0

(2 + x) y^{^{'}} = 2 y

(dx)/(dt)-0.04x=5000,x(0)=18000

\frac{d x}{d t} - 0.04 x = 5000, x (0) = 18000

y^'=(y^2)/(x^2y+xy)

y^{^{'}} = \frac{y ^{2}}{x ^{2} y + x y}

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'=1+y,y(1)=3 ?
The solution for x^2y^'=1+y,y(1)=3 is y=4e^{-1/x+1}-1