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Popular >

y^'=(y^2)/(x^2y+xy)

Solution

y^{^{'}} = \frac{y ^{2}}{x ^{2} y + x y}

Solution

y = \frac{c _{1} x}{x + 1}

Solution steps

y^{'} (x) = \frac{y ^{2}}{x ^{2} y + x y}

Solve separable ODE:

y = \frac{c _{1} x}{x + 1}

y = \frac{c _{1} x}{x + 1}

Popular Examples

(dy)/(dx)y=x(2x+1)^{1/3}

\frac{d y}{d x} y = x (2 x + 1)^{\frac{1}{3}}

(dy}{dx}=\frac{ln(2))/7 y-80000

\frac{d y}{d x} = \frac{ln ( 2 )}{7} y - 80000

(dy)/(dx)=3*(y^5)/(x^4)

\frac{d y}{d x} = 3 \cdot \frac{y ^{5}}{x ^{4}}

y^{^{'}} = - \frac{37 t}{y}

(dy)/(dx)=(1+x+x^2)y

\frac{d y}{d x} = (1 + x + x^{2}) y

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y^2)/(x^2y+xy) ?
The solution for y^'=(y^2)/(x^2y+xy) is y=(c_{1}x)/(x+1)