What is the solution for y^'=-(37t)/y ?

The solution for y^'=-(37t)/y is y=sqrt(-37t^2+c_{1)},y=-sqrt(-37t^2+c_{1)}

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y^'=-(37t)/y

y^{^{'}} = - \frac{37 t}{y}

y = - 37 t^{2} + c_{1}, y = - - 37 t^{2} + c_{1}

Solution steps

y^{'} (t) = - \frac{37 t}{y}

Solve separable ODE:

y = - 37 t^{2} + c_{1}, y = - - 37 t^{2} + c_{1}

y = - 37 t^{2} + c_{1}, y = - - 37 t^{2} + c_{1}

\frac{d y}{d x} = (1 + x + x^{2}) y

y^{^{'}} = 7 e^{3 x - 5 y}

\frac{d V}{d t} = (10 - \frac{4}{100} V), V (0) = 0

\frac{d v}{df} = v \cdot f

y e^{x} \frac{d y}{d x} = e^{- y} + e^{- 3 x - y}

What is the solution for y^'=-(37t)/y ?
The solution for y^'=-(37t)/y is y=sqrt(-37t^2+c_{1)},y=-sqrt(-37t^2+c_{1)}