What is the derivative of \sqrt[8]{x}+\sqrt[7]{x} ?

The derivative of \sqrt[8]{x}+\sqrt[7]{x} is 1/(8x^{7/8)}+1/(7x^{6/7)}

What is the first derivative of \sqrt[8]{x}+\sqrt[7]{x} ?

The first derivative of \sqrt[8]{x}+\sqrt[7]{x} is 1/(8x^{7/8)}+1/(7x^{6/7)}

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derivative of

\frac{1}{8 x ^{\frac{7}{8}}} + \frac{1}{7 x ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{8 x ^{\frac{7}{8}}} + \frac{1}{7 x ^{\frac{6}{7}}}

\frac{\partial}{\partial x} (\frac{x + 4}{y + 5})

y^{^{'}} = \frac{y}{x ln ( x )}

110 x - 16 x^{2}

\frac{d}{d x} (16)

\int \frac{7 - 6 x ^{3} + 4 x ^{6}}{x ^{6}} d x

What is the derivative of \sqrt[8]{x}+\sqrt[7]{x} ?
The derivative of \sqrt[8]{x}+\sqrt[7]{x} is 1/(8x^{7/8)}+1/(7x^{6/7)}
What is the first derivative of \sqrt[8]{x}+\sqrt[7]{x} ?
The first derivative of \sqrt[8]{x}+\sqrt[7]{x} is 1/(8x^{7/8)}+1/(7x^{6/7)}