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Popular >

x^3y^'=y(x^3+x^2)

Solution

x^{3} y^{^{'}} = y (x^{3} + x^{2})

Solution

y = e^{x + c_{1}} x

Solution steps

x^{3} y^{'} (x) = y (x^{3} + x^{2})

Solve separable ODE:

y = e^{x + c_{1}} x

y = e^{x + c_{1}} x

Popular Examples

x^2(dy)/(dx)=(y-xy)

x^{2} \frac{d y}{d x} = (y - x y)

2zuduudu+u^2dz=0

2 z u d uu d u + u^{2} d z = 0

(dy)/(dx)=(y-1)^2e^{x-7},y(7)=2

\frac{d y}{d x} = (y - 1)^{2} e^{x - 7}, y (7) = 2

(dx)/(dt)= 1/(xe^{t+9x)}

\frac{d x}{d t} = \frac{1}{x e ^{t + 9 x}}

(dy)/(dx)=(x^5y)/(sqrt(16-x^6))

\frac{d y}{d x} = \frac{x ^{5} y}{16 - x ^{6}}

Frequently Asked Questions (FAQ)

What is the solution for x^3y^'=y(x^3+x^2) ?
The solution for x^3y^'=y(x^3+x^2) is y=e^{x+c_{1}}x