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Popular >

y^'-2y=0,y(x,1)=x^2

Solution

y^{^{'}} - 2 y = 0, y (x, 1) = x^{2}

Solution

y = e^{2 x + c_{1}}

Solution steps

y^{'} (x) - 2 y = 0

Solve separable ODE:

y = e^{2 x + c_{1}}

y = e^{2 x + c_{1}}

Graph

Popular Examples

y^'+3.2x^4*y=6.4x^4

y^{^{'}} + 3.2 x^{4} \cdot y = 6.4 x^{4}

(dy)/(dx)= x/(y(5x+1))

\frac{d y}{d x} = \frac{x}{y ( 5 x + 1 )}

(x^2-9)/x y^'+y=0

\frac{x ^{2} - 9}{x} y^{^{'}} + y = 0

(dy)/(dx)=1+1/5 y

\frac{d y}{d x} = 1 + \frac{1}{5} y

((x^2-9))/x*(dy)/(dx)+y=0,y(5)=1

\frac{( x ^{2} - 9 )}{x} \cdot \frac{d y}{d x} + y = 0, y (5) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'-2y=0,y(x,1)=x^2 ?
The solution for y^'-2y=0,y(x,1)=x^2 is y=e^{2x+c_{1}}