en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5(dv)/(dt)=-2v^2

Solution

5 \frac{d v}{d t} = - 2 v^{2}

Solution

v = - \frac{5}{- 2 t + c _{1}}

Solution steps

5 \frac{d v}{d t} = - 2 v^{2}

Solve separable ODE:

v = - \frac{5}{- 2 t + c _{1}}

v = - \frac{5}{- 2 t + c _{1}}

Popular Examples

y^{^{'}} = 3 x 2 y

derivative of f(x^{-1})f(x)= 1/5 x+5,x=6

\frac{d}{d x} (f (x)^{- 1}) f (x) = \frac{1}{5} x + 5, x = 6

x(dy)/(dx)=x^2y^2

x \frac{d y}{d x} = x^{2} y^{2}

(dy)/(dx)=y^2*x^3

\frac{d y}{d x} = y^{2} \cdot x^{3}

y^{5/2}(dy)/(dx)-y^2=-y^{7/2}

y^{\frac{5}{2}} \frac{d y}{d x} - y^{2} = - y^{\frac{7}{2}}

Frequently Asked Questions (FAQ)

What is the solution for 5(dv)/(dt)=-2v^2 ?
The solution for 5(dv)/(dt)=-2v^2 is v=-5/(-2t+c_{1)}