What is the solution for (dy)/(dt)=0.03(291-y) ?

The solution for (dy)/(dt)=0.03(291-y) is y=-e^{-(3t)/(100)-c_{1}}+291

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(dy)/(dt)=0.03(291-y)

\frac{d y}{d t} = 0.03 (291 - y)

y = - e^{- \frac{3 t}{100} - c_{1}} + 291

Solution steps

\frac{d y}{d t} = 0.03 (291 - y)

Solve separable ODE:

y = - e^{- \frac{3 t}{100} - c_{1}} + 291

y = - e^{- \frac{3 t}{100} - c_{1}} + 291

\frac{d y}{d x} = \frac{cos ( 5 x )}{4 y ^{3}}

y^{^{'}} + 2 y = 4 x y

\frac{d x}{d y} = \frac{( x + 2 ) ^{2}}{x}

(1 + x^{2}) \frac{d y}{d x} - x y = 0, y (2) = 5

\frac{d y}{d x} = 2 (1 - x^{2}) (1 - y^{2})

What is the solution for (dy)/(dt)=0.03(291-y) ?
The solution for (dy)/(dt)=0.03(291-y) is y=-e^{-(3t)/(100)-c_{1}}+291