en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=y(4x^6+5)

Solution

y^{^{'}} = y (4 x^{6} + 5)

Solution

y = e^{\frac{4 x ^{7}}{7} + 5 x + c_{1}}

Solution steps

y^{'} (x) = y (4 x^{6} + 5)

Solve separable ODE:

y = e^{\frac{4 x ^{7}}{7} + 5 x + c_{1}}

y = e^{\frac{4 x ^{7}}{7} + 5 x + c_{1}}

Graph

Popular Examples

y^'= y/(x+sqrt(+x))

y^{^{'}} = \frac{y}{x + + x}

(dy)/(dx)y=x^2+2x+3

\frac{d y}{d x} y = x^{2} + 2 x + 3

x^'=x^{100}(t^2-1)(t^2-9),x(0)=1

x^{^{'}} = x^{100} (t^{2} - 1) (t^{2} - 9), x (0) = 1

y^'=2xy^2,y(2)=1

y^{^{'}} = 2 x y^{2}, y (2) = 1

(dy)/(dx)xy=x^2-x

\frac{d y}{d x} x y = x^{2} - x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y(4x^6+5) ?
The solution for y^'=y(4x^6+5) is y=e^{(4x^7)/7+5x+c_{1}}