What is the solution for xy^'-y=4x^9y,y(1)=10 ?

The solution for xy^'-y=4x^9y,y(1)=10 is y=10e^{(4x^9-4)/9}x

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xy^'-y=4x^9y,y(1)=10

x y^{^{'}} - y = 4 x^{9} y, y (1) = 10

y = 10 e^{\frac{4 x ^{9} - 4}{9}} x

Solution steps

x y^{'} (x) - y = 4 x^{9} y

Solve separable ODE:

y = 10 e^{\frac{4 x ^{9} - 4}{9}} x

y = 10 e^{\frac{4 x ^{9} - 4}{9}} x

y^{^{'}} = \frac{x ^{2} - 7}{y ^{2}}, y (0) = 4

x^{^{'}} = \frac{1}{x ^{3} - x}, x (0) = - 2

\frac{d y}{d x} = y^{4} cos (x)

\frac{d r}{d t} = 4 r t

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{4}

What is the solution for xy^'-y=4x^9y,y(1)=10 ?
The solution for xy^'-y=4x^9y,y(1)=10 is y=10e^{(4x^9-4)/9}x