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Popular >

y^'=(2/t-t)y

Solution

y^{^{'}} = (\frac{2}{t} - t) y

Solution

y = e^{- \frac{t ^{2}}{2} + c_{1}} t^{2}

Solution steps

y^{'} (t) = (\frac{2}{t} - t) y

Solve separable ODE:

y = e^{- \frac{t ^{2}}{2} + c_{1}} t^{2}

y = e^{- \frac{t ^{2}}{2} + c_{1}} t^{2}

Graph

Popular Examples

(ux)^2udx+xdu+x^2+(x)(ux)+(ux)^2=0

(ux)^{2} u d x + x d u + x^{2} + (x) (ux) + (ux)^{2} = 0

\frac{d r}{d t} = - r

y = x \frac{d y}{d x}

y^'-2e^xy=-2e^x

y^{^{'}} - 2 e^{x} y = - 2 e^{x}

f(x)=3sin(5x)f^'(x)((4pi))/(15)

f (x) = 3 sin (5 x) f^{^{'}} (x) \frac{( 4 π )}{15}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2/t-t)y ?
The solution for y^'=(2/t-t)y is y=e^{-(t^2)/2+c_{1}}t^2