What is the solution for y^'=(y^42x)/(4y^3x^2) ?

The solution for y^'=(y^42x)/(4y^3x^2) is y=c_{1}sqrt(x)

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y^'=(y^42x)/(4y^3x^2)

y^{^{'}} = \frac{y ^{4} 2 x}{4 y ^{3} x ^{2}}

y = c_{1} x

Solution steps

y^{'} (x) = \frac{y ^{4} 2 x}{4 y ^{3} x ^{2}}

Solve separable ODE:

y = c_{1} x

y = c_{1} x

y^{^{'}} = \frac{3 x 1 + y ^{2}}{y}

\frac{d y}{y} = d x (x - 1)

\frac{d y}{d x} y = ln (7) x^{2}

\frac{d y}{d x} = (x - 5) e^{- 2 y}, y (2) = ln (5)

\frac{d y}{d x} = x^{2} + x^{2} y^{2}

What is the solution for y^'=(y^42x)/(4y^3x^2) ?
The solution for y^'=(y^42x)/(4y^3x^2) is y=c_{1}sqrt(x)