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Popular >

y^'-xy^2=x

Solution

y^{^{'}} - x y^{2} = x

Solution

y = tan (\frac{x ^{2}}{2} + c_{1})

Solution steps

y^{'} (x) - x y^{2} = x

Solve separable ODE:

y = tan (\frac{x ^{2}}{2} + c_{1})

y = tan (\frac{x ^{2}}{2} + c_{1})

Graph

Popular Examples

y^{^{'}} = - 5 y + 20

(dy)/(dx)y= 1/(sqrt(1-x^2))

\frac{d y}{d x} y = \frac{1}{1 - x ^{2}}

2xy+(1+x^2)*y^'=0

2 x y + (1 + x^{2}) \cdot y^{^{'}} = 0

y^'=8tcos^2(y),y(1)=(3pi)/4

y^{^{'}} = 8 t cos^{2} (y), y (1) = \frac{3 π}{4}

derivative of (x^8/(y^5))=0

\frac{d}{d x} (\frac{x ^{8}}{y ^{5}}) = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'-xy^2=x ?
The solution for y^'-xy^2=x is y=tan((x^2)/2+c_{1})