What is the solution for (dy)/(dx)=(x-1)/(y^2) ?

The solution for (dy)/(dx)=(x-1)/(y^2) is y=\sqrt[3]{(3x^2)/2-3x+c_{1}}

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(dy)/(dx)=(x-1)/(y^2)

\frac{d y}{d x} = \frac{x - 1}{y ^{2}}

y = 3 \frac{3 x ^{2}}{2} - 3 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x - 1}{y ^{2}}

Solve separable ODE:

y = 3 \frac{3 x ^{2}}{2} - 3 x + c_{1}

y = 3 \frac{3 x ^{2}}{2} - 3 x + c_{1}

y^{^{'}} \cdot ln (y) = y

x = \frac{y}{y ^{^{'}} + y}

20 (\frac{d v}{d t}) = - (20) (32) - 0.0025 v

\frac{d y}{d x} \cdot (1 + e^{x}) = e^{x - y}

y^{^{'}} = - 9.8 - \frac{0.0025}{4} y

What is the solution for (dy)/(dx)=(x-1)/(y^2) ?
The solution for (dy)/(dx)=(x-1)/(y^2) is y=\sqrt[3]{(3x^2)/2-3x+c_{1}}