What is the solution for (dy)/(dx)=2x^3y^4 ?

The solution for (dy)/(dx)=2x^3y^4 is y=-\sqrt[3]{2/(3(x^4+c_{1))}}

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(dy)/(dx)=2x^3y^4

\frac{d y}{d x} = 2 x^{3} y^{4}

y = - 3 \frac{2}{3 ( x ^{4} + c _{1} )}

Solution steps

\frac{d y}{d x} = 2 x^{3} y^{4}

Solve separable ODE:

y = - 3 \frac{2}{3 ( x ^{4} + c _{1} )}

y = - 3 \frac{2}{3 ( x ^{4} + c _{1} )}

\frac{( d y )}{( d x ) - 3 y} = x^{(6)}

\frac{d x}{sin ( y )} + \frac{d y}{cos ( x )} = 0

x^{6} y^{^{'}} + 13 x^{5} y = 0

y^{^{'}} x = (1 - y^{2})^{\frac{1}{2}}

y^{^{'}} - x^{5} y^{4} = 0, y (0) = 2, y (2) = a

What is the solution for (dy)/(dx)=2x^3y^4 ?
The solution for (dy)/(dx)=2x^3y^4 is y=-\sqrt[3]{2/(3(x^4+c_{1))}}