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Popular >

y^'=-3/7 e^{3y}

Solution

y^{^{'}} = - \frac{3}{7} e^{3 y}

Solution

y = - \frac{ln ( \frac{9 t + c _{1}}{7} )}{3}

Solution steps

y^{'} (t) = - \frac{3}{7} e^{3 y}

Solve separable ODE:

y = - \frac{ln ( \frac{9 t + c _{1}}{7} )}{3}

y = - \frac{ln ( \frac{9 t + c _{1}}{7} )}{3}

Graph

Popular Examples

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\frac{d y}{d x} = 6 y ln (\frac{2}{y})

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- \frac{d h}{d t} = 5 h

ln(x)y^'-(2sqrt(y))/x =0

ln (x) y^{^{'}} - \frac{2 y}{x} = 0

3e^{7x}(dy)/(dx)=-49 x/(y^2),y(0)=1

3 e^{7 x} \frac{d y}{d x} = - 49 \frac{x}{y ^{2}}, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=-3/7 e^{3y} ?
The solution for y^'=-3/7 e^{3y} is y=-(ln((9t+c_{1})/7))/(3)