What is the solution for (dy)/(dx)x^2+4xy=y ?

The solution for (dy)/(dx)x^2+4xy=y is y=(e^{(-1+c_{1}x)/x})/(x^4)

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(dy)/(dx)x^2+4xy=y

\frac{d y}{d x} x^{2} + 4 x y = y

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x ^{4}}

Solution steps

\frac{d y}{d x} x^{2} + 4 x y = y

Solve separable ODE:

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x ^{4}}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x ^{4}}

y^{^{'}} - y sin (3 x) = 0

d y = \frac{( y + 4 )}{x + 5} d x

\frac{d y}{d x} y = \frac{1 - 2 x ^{2}}{x ^{4} - 2 x ^{2} + 6}

y d x + (\frac{x - 1}{2 x ^{3} y}) d y = 0

\frac{d y}{d x} 3 x^{2} - 3 y^{2} = 4

What is the solution for (dy)/(dx)x^2+4xy=y ?
The solution for (dy)/(dx)x^2+4xy=y is y=(e^{(-1+c_{1}x)/x})/(x^4)