What is the solution for (dy)/(dx)=(4ycos(x))/((3+cos^2(x))) ?

The solution for (dy)/(dx)=(4ycos(x))/((3+cos^2(x))) is y=(e^{c_{1}}sin(x)+2e^{c_{1}})/(sin(x)-2)

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(dy)/(dx)=(4ycos(x))/((3+cos^2(x)))

\frac{d y}{d x} = \frac{4 y cos ( x )}{( 3 + cos ^{2} ( x ) )}

y = \frac{e ^{c_{1}} sin ( x ) + 2 e ^{c_{1}}}{sin ( x ) - 2}

Solution steps

\frac{d y}{d x} = \frac{4 y cos ( x )}{( 3 + cos ^{2} ( x ) )}

Solve separable ODE:

y = \frac{e ^{c_{1}} sin ( x ) + 2 e ^{c_{1}}}{sin ( x ) - 2}

y = \frac{e ^{c_{1}} sin ( x ) + 2 e ^{c_{1}}}{sin ( x ) - 2}

\frac{d y}{d x} = - y + 2

u^{^{'}} cos (H (t)) = 8

x^{^{'}} = - x - 2

(4 + 5 t) y^{^{'}} + 5 y = - 1

y^{^{'}} = x^{4} \cdot y^{- 1}, y (0) = 7

What is the solution for (dy)/(dx)=(4ycos(x))/((3+cos^2(x))) ?
The solution for (dy)/(dx)=(4ycos(x))/((3+cos^2(x))) is y=(e^{c_{1}}sin(x)+2e^{c_{1}})/(sin(x)-2)