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Popular >

-9y^'+3y=8

Solution

- 9 y^{^{'}} + 3 y = 8

Solution

y = - \frac{e ^{\frac{t + c _{1}}{3}}}{3} + \frac{8}{3}

Solution steps

- 9 y^{'} (t) + 3 y = 8

Solve separable ODE:

y = - \frac{e ^{\frac{t + c _{1}}{3}}}{3} + \frac{8}{3}

y = - \frac{e ^{\frac{t + c _{1}}{3}}}{3} + \frac{8}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for -9y^'+3y=8 ?
The solution for -9y^'+3y=8 is y=-(e^{(t+c_{1})/3})/(3)+8/3