What is the solution for cos^2(x)(dy)/(dx)=y^2sin^2(x) ?

The solution for cos^2(x)(dy)/(dx)=y^2sin^2(x) is y=-1/(-x+tan(x)+c_{1)}

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cos^2(x)(dy)/(dx)=y^2sin^2(x)

cos^{2} (x) \frac{d y}{d x} = y^{2} sin^{2} (x)

y = - \frac{1}{- x + tan ( x ) + c _{1}}

Solution steps

cos^{2} (x) \frac{d y}{d x} = y^{2} sin^{2} (x)

Solve separable ODE:

y = - \frac{1}{- x + tan ( x ) + c _{1}}

y = - \frac{1}{- x + tan ( x ) + c _{1}}

(- y - 2) d x + (x - 2) d y = 0

\frac{d x}{d t} x = t^{2} - 5

\frac{d y}{d t} = 100 - y, y (0) = 20

\frac{d x}{d t} = 30 - 11 x + x^{2}

\frac{d}{d x} (x y) = \frac{d}{d x} (x + y)

What is the solution for cos^2(x)(dy)/(dx)=y^2sin^2(x) ?
The solution for cos^2(x)(dy)/(dx)=y^2sin^2(x) is y=-1/(-x+tan(x)+c_{1)}