What is the solution for (dy)/(dx)=6e^{2x-y},y(0)=0 ?

The solution for (dy)/(dx)=6e^{2x-y},y(0)=0 is y=ln(3e^{2x}-2)

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(dy)/(dx)=6e^{2x-y},y(0)=0

\frac{d y}{d x} = 6 e^{2 x - y}, y (0) = 0

y = ln (3 e^{2 x} - 2)

Solution steps

\frac{d y}{d x} = 6 e^{2 x - y}

Solve separable ODE:

y = ln (3 e^{2 x} - 2)

y = ln (3 e^{2 x} - 2)

5 x y d x - ln^{8} (y) d y = 0

y^{^{'}} = \frac{1}{3} y

\frac{d y}{d x} y = u^{2} - 2 u, u = \frac{1}{x ^{2}}

3 = \frac{π}{12} \frac{d}{d t} ((h (t))^{3})

2 sin (3 x) sin (2 y) d y = 3 cos (3 x) cos (2 y) d x

What is the solution for (dy)/(dx)=6e^{2x-y},y(0)=0 ?
The solution for (dy)/(dx)=6e^{2x-y},y(0)=0 is y=ln(3e^{2x}-2)