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Popular >

y^'+y/5 =3,y(-1)=0

Solution

y^{^{'}} + \frac{y}{5} = 3, y (- 1) = 0

Solution

y = - 15 e^{\frac{- t - 1}{5}} + 15

Solution steps

y^{'} (t) + \frac{y}{5} = 3

Solve separable ODE:

y = - 15 e^{\frac{- t - 1}{5}} + 15

y = - 15 e^{\frac{- t - 1}{5}} + 15

Graph

Popular Examples

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Frequently Asked Questions (FAQ)

What is the solution for y^'+y/5 =3,y(-1)=0 ?
The solution for y^'+y/5 =3,y(-1)=0 is y=-15e^{(-t-1)/5}+15