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Popular >

y^'-2y=g

Solution

y^{^{'}} - 2 y = g

Solution

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{g}{2}

Solution steps

y^{'} (t) - 2 y = g

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{g}{2}

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{g}{2}

Graph

Popular Examples

5x(y^2+7)dx-ydy=0

5 x (y^{2} + 7) d x - y d y = 0

(dS)/(dt)=0.05-0.00375*S,S(0)=0

\frac{d S}{d t} = 0.05 - 0.00375 \cdot S, S (0) = 0

derivative of 2yln(y)=(dx)/(dx)

\frac{d}{d x} (2 y ln (y)) = \frac{d x}{d x}

(dy)/(dx)=x^2y^5

\frac{d y}{d x} = x^{2} y^{5}

d/(dθ)(ln(y(θ)))=(θ-3)/(θcos(θ))

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 3}{θ cos ( θ )}

Frequently Asked Questions (FAQ)

What is the solution for y^'-2y=g ?
The solution for y^'-2y=g is y=(e^{2t+c_{1}})/2-g/2