What is the solution for (dy)/(dx)=3x^2(y^2+4) ?

The solution for (dy)/(dx)=3x^2(y^2+4) is y=2tan(2x^3+c_{1})

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(dy)/(dx)=3x^2(y^2+4)

\frac{d y}{d x} = 3 x^{2} (y^{2} + 4)

y = 2 tan (2 x^{3} + c_{1})

Solution steps

\frac{d y}{d x} = 3 x^{2} (y^{2} + 4)

Solve separable ODE:

y = 2 tan (2 x^{3} + c_{1})

y = 2 tan (2 x^{3} + c_{1})

\frac{df}{d t} = - 0.01 \cdot f (t)^{(1.84)}

x^{2} sin (y) d x - cot (y) d y = 0

\frac{d x}{d t} = 0.09 - \frac{x}{2580}

\frac{d y}{d x} + (x^{2} - 2) y = x^{2} - 2

y^{^{'}} + 9 y^{3} = 0, y (0) = y^{0}

What is the solution for (dy)/(dx)=3x^2(y^2+4) ?
The solution for (dy)/(dx)=3x^2(y^2+4) is y=2tan(2x^3+c_{1})