What is the solution for (dy)/(dx)y=((5x^2+2)(3x+9))/(8x-9) ?

The solution for (dy)/(dx)y=((5x^2+2)(3x+9))/(8x-9) is

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(dy)/(dx)y=((5x^2+2)(3x+9))/(8x-9)

\frac{d y}{d x} y = \frac{( 5 x ^{2} + 2 ) ( 3 x + 9 )}{8 x - 9}

y = \frac{2560 x ^{3} + 15840 x ^{2} + 38712 x + 52767 ln ( 8 x - 9 ) + c _{1}}{32 2}, y = - \frac{2560 x ^{3} + 15840 x ^{2} + 38712 x + 52767 ln ( 8 x - 9 ) + c _{1}}{32 2}

Solution steps

\frac{d y}{d x} y = \frac{( 5 x ^{2} + 2 ) ( 3 x + 9 )}{8 x - 9}

Solve separable ODE:

y = \frac{2560 x ^{3} + 15840 x ^{2} + 38712 x + 52767 ln ( 8 x - 9 ) + c _{1}}{32 2}, y = - \frac{2560 x ^{3} + 15840 x ^{2} + 38712 x + 52767 ln ( 8 x - 9 ) + c _{1}}{32 2}

y = \frac{2560 x ^{3} + 15840 x ^{2} + 38712 x + 52767 ln ( 8 x - 9 ) + c _{1}}{32 2}, y = - \frac{2560 x ^{3} + 15840 x ^{2} + 38712 x + 52767 ln ( 8 x - 9 ) + c _{1}}{32 2}

(1 - x^{2}) y^{^{'}} = 6 x y, y (0) = 3

3 e^{2 x} \frac{d y}{d x} = - 4 \cdot \frac{x}{y ^{2}}

\frac{d y}{d x} = \frac{( 1 - y )}{xv}

y^{^{'}} = 1 - \frac{y}{10}

4 \frac{d y}{d t} - \frac{1}{2} \frac{d y}{d t} = a + 32 - 4 y

What is the solution for (dy)/(dx)y=((5x^2+2)(3x+9))/(8x-9) ?
The solution for (dy)/(dx)y=((5x^2+2)(3x+9))/(8x-9) is