What is the solution for (dy)/(dx)=e^{x+y},e^x+e^y=c ?

The solution for (dy)/(dx)=e^{x+y},e^x+e^y=c is y=-ln(-e^x-c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=e^{x+y},e^x+e^y=c

\frac{d y}{d x} = e^{x + y}, e^{x} + e^{y} = c

y = - ln (- e^{x} - c_{1})

Solution steps

\frac{d y}{d x} = e^{x + y}

Solve separable ODE:

y = - ln (- e^{x} - c_{1})

y = - ln (- e^{x} - c_{1})

2 x \frac{d y}{d x} - 6 y = 0

2 d x - e^{y - x} d y = 0

y^{2} = x (x + 2) \frac{d y}{d x}

\frac{d S}{d t} = 0.06 - \frac{3 S}{1420}, t = 10

\frac{d x}{d t} = \frac{5}{x e ^{t + 4 x}}

What is the solution for (dy)/(dx)=e^{x+y},e^x+e^y=c ?
The solution for (dy)/(dx)=e^{x+y},e^x+e^y=c is y=-ln(-e^x-c_{1})