What is the solution for (\frac{dy)/(dt)}{y-49}=-1/5 ?

The solution for (\frac{dy)/(dt)}{y-49}=-1/5 is y=e^{-1/5 t+c_{1}}+49

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(\frac{dy)/(dt)}{y-49}=-1/5

\frac{\frac{d y}{d t}}{y - 49} = - \frac{1}{5}

y = e^{- \frac{1}{5} t + c_{1}} + 49

Solution steps

\frac{\frac{d y}{d t}}{y - 49} = - \frac{1}{5}

Solve separable ODE:

y = e^{- \frac{1}{5} t + c_{1}} + 49

y = e^{- \frac{1}{5} t + c_{1}} + 49

y^{^{'}} (s) (- s^{2} - 2 s) - 2 sy (s) = 0

\frac{d y}{d x} y = (csc (x) - cot (x))^{- 1}

y^{^{'}} + 36 y = 0

4 t \frac{d y}{d t} + y = 0

\frac{( v + 1 ) d v}{v ^{2}} = \frac{- 2 d x}{x}

What is the solution for (\frac{dy)/(dt)}{y-49}=-1/5 ?
The solution for (\frac{dy)/(dt)}{y-49}=-1/5 is y=e^{-1/5 t+c_{1}}+49