What is the solution for 3x+2y^2dx+2xydy=0 ?

The solution for 3x+2y^2dx+2xydy=0 is y= 3/(2\W(\frac{3x){c_{1}})}

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3x+2y^2dx+2xydy=0

3 x + 2 y^{2} d x + 2 x y d y = 0

y = \frac{3}{2 W ( \frac{3 x}{c _{1}} )}

Solution steps

3 x + 2 y^{2} d x + 2 x y d y = 0

Solve separable ODE:

y = \frac{3}{2 W ( \frac{3 x}{c _{1}} )}

y = \frac{3}{2 W ( \frac{3 x}{c _{1}} )}

v^{2} x d x + v x^{2} d v + vx d x + x^{2} d v = vx d x - x d x

\frac{d y}{y - 4} = x^{4} d x

\frac{d y}{d x} = x^{3} (y - 2), y (0) = 4

y^{^{'}} = y cos (x), y (0) = 5

y^{^{'}} = 6 x y + 42 x - 4 y - 28

What is the solution for 3x+2y^2dx+2xydy=0 ?
The solution for 3x+2y^2dx+2xydy=0 is y= 3/(2\W(\frac{3x){c_{1}})}