What is the derivative of (x^3/3+1/(4x)) ?

The derivative of (x^3/3+1/(4x)) is x^2-1/(4x^2)

What is the first derivative of (x^3/3+1/(4x)) ?

The first derivative of (x^3/3+1/(4x)) is x^2-1/(4x^2)

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\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{1}{4 x})

x^{2} - \frac{1}{4 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{1}{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (\frac{1}{4 x})

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{1}{4 x}) = - \frac{1}{4 x ^{2}}

= x^{2} - \frac{1}{4 x ^{2}}

\int \frac{1}{( x - 3 ) ( x - 2 )} d x

\int arcsin (t) d t

\frac{\partial}{\partial x} (2 x^{2} - 5 y^{2})

\int_{- 2}^{6} 4 x - x^{2} + 12 d x

\int_{5}^{7} [\frac{k}{2} x^{2}] d x

What is the derivative of (x^3/3+1/(4x)) ?
The derivative of (x^3/3+1/(4x)) is x^2-1/(4x^2)
What is the first derivative of (x^3/3+1/(4x)) ?
The first derivative of (x^3/3+1/(4x)) is x^2-1/(4x^2)