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Popular >

(x^2-9)y^'+xy=0

Solution

(x^{2} - 9) \cdot y^{^{'}} + x \cdot y = 0

Solution

y = \frac{c _{1}}{x ^{2} - 9}

Solution steps

(x^{2} - 9) \cdot y^{'} (x) + x \cdot y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9}

y = \frac{c _{1}}{x ^{2} - 9}

Graph

Popular Examples

y^'=2*sqrt(y+1)*cos(x)

y^{^{'}} = 2 \cdot y + 1 \cdot cos (x)

2x(y+1)+(x^2+6)(dy)/(dx)=0

2 x (y + 1) + (x^{2} + 6) \frac{d y}{d x} = 0

y^{^{'}} = - y, y (0) = 5

y^'(x)=(ycos(x))/(1+2y^2),y(0)=1

y^{^{'}} (x) = \frac{y cos ( x )}{1 + 2 y ^{2}}, y (0) = 1

(dt)/(dy)=2t*y^2

\frac{d t}{d y} = 2 t \cdot y^{2}

Frequently Asked Questions (FAQ)

What is the solution for (x^2-9)*y^'+x*y=0 ?
The solution for (x^2-9)*y^'+x*y=0 is y=(c_{1})/(sqrt(x^2-9))