What is the solution for (ln(y))^3((dy)/(dx))=x^3y,y(1)=e^2 ?

The solution for (ln(y))^3((dy)/(dx))=x^3y,y(1)=e^2 is y=e^{\sqrt[4]{x^4+15}}

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(ln(y))^3((dy)/(dx))=x^3y,y(1)=e^2

(ln (y))^{3} (\frac{d y}{d x}) = x^{3} y, y (1) = e^{2}

y = e^{4 x^{4} + 15}

Solution steps

(ln (y))^{3} (\frac{d y}{d x}) = x^{3} y

Solve separable ODE:

y = e^{4 x^{4} + 15}

y = e^{4 x^{4} + 15}

\frac{d y}{d x} = k 2 y + a

(y^{^{'}}) = e^{x} e^{y}

\frac{1}{x} d x + \frac{1}{2 y} d y = 0

(t^{2} + 1) y^{^{'}} = sin (t^{2} + 3 cos (t)) y

\frac{d y}{d x} = cos^{2} (y), \frac{π}{2} < y

What is the solution for (ln(y))^3((dy)/(dx))=x^3y,y(1)=e^2 ?
The solution for (ln(y))^3((dy)/(dx))=x^3y,y(1)=e^2 is y=e^{\sqrt[4]{x^4+15}}