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Popular >

1/x dx+1/(2y)dy=0

Solution

\frac{1}{x} d x + \frac{1}{2 y} d y = 0

Solution

y = \frac{c _{1}}{x ^{2}}

Solution steps

\frac{1}{x} d x + \frac{1}{2 y} d y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}}

y = \frac{c _{1}}{x ^{2}}

Graph

Popular Examples

(t^2+1)y^'=sin(t^2+3cos(t))y

(t^{2} + 1) y^{^{'}} = sin (t^{2} + 3 cos (t)) y

(dy)/(dx)=cos^2(y), pi/2 <y

\frac{d y}{d x} = cos^{2} (y), \frac{π}{2} < y

(dy)/(dx)(sqrt(y/x))y=(sqrt(x)+c^1)^2

\frac{d y}{d x} (\frac{y}{x}) y = (x + c^{1})^{2}

y^{^{'}} + 2 x \cdot y = 0

2y(y^')=6t^2,y(0)=5

2 y (y^{^{'}}) = 6 t^{2}, y (0) = 5

Frequently Asked Questions (FAQ)

What is the solution for 1/x dx+1/(2y)dy=0 ?
The solution for 1/x dx+1/(2y)dy=0 is y=(c_{1})/(x^2)