What is the solution for 7xydx-4xdy=7xydy-8ydx ?

The solution for 7xydx-4xdy=7xydy-8ydx is y=(4\W((x^2*7)/(4e^{\frac{-7x-c_{1))/4}})}{7}

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7xydx-4xdy=7xydy-8ydx

7 x y d x - 4 x d y = 7 x y d y - 8 y d x

y = \frac{4 W ( \frac{x ^{2} \cdot 7}{4 e ^{\frac{- 7 x - c _{1}}{4}}} )}{7}

Solution steps

7 x y d x - 4 x d y = 7 x y d y - 8 y d x

Solve separable ODE:

y = \frac{4 W ( \frac{x ^{2} \cdot 7}{4 e ^{\frac{- 7 x - c _{1}}{4}}} )}{7}

y = \frac{4 W ( \frac{x ^{2} \cdot 7}{4 e ^{\frac{- 7 x - c _{1}}{4}}} )}{7}

y^{^{'}} = 7 x y

\frac{d y}{d x} = y^{2} a - 1

y^{^{'}} = \frac{x}{cos ( y )}, y (1) = 0

x - x^{2} d y - x y d x = 0

\frac{d y}{d x} = \frac{3 x y}{( ln ( y ) ) ^{4}}

What is the solution for 7xydx-4xdy=7xydy-8ydx ?
The solution for 7xydx-4xdy=7xydy-8ydx is y=(4\W((x^2*7)/(4e^{\frac{-7x-c_{1))/4}})}{7}