What is the solution for x^'=e^x*t*cos(t) ?

The solution for x^'=e^x*t*cos(t) is x=-ln(-tsin(t)-cos(t)-c_{1})

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x^'=e^xtcos(t)

x^{^{'}} = e^{x} \cdot t \cdot cos (t)

x = - ln (- t sin (t) - cos (t) - c_{1})

Solution steps

x^{'} (t) = e^{x} \cdot t \cdot cos (t)

Solve separable ODE:

x = - ln (- t sin (t) - cos (t) - c_{1})

x = - ln (- t sin (t) - cos (t) - c_{1})

\frac{d P}{d t} = 4 Pt, P (1) = 6

\frac{d p}{d t} = 6 p (14 - ln (p))

\frac{x d y}{d x} = y^{2}

2 (\frac{d q}{d t}) + 6 q = 2

\frac{2 x}{a ^{2}} + \frac{2 y \frac{d y}{d x}}{b ^{2}} = 0

What is the solution for x^'=e^x*t*cos(t) ?
The solution for x^'=e^x*t*cos(t) is x=-ln(-tsin(t)-cos(t)-c_{1})