What is the solution for (dy)/(dx)y=sqrt(u),u=x^2+2 ?

The solution for (dy)/(dx)y=sqrt(u),u=x^2+2 is y=sqrt(2\sqrt{u)x+c_{1}},y=-sqrt(2\sqrt{u)x+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)y=sqrt(u),u=x^2+2

\frac{d y}{d x} y = u, u = x^{2} + 2

y = 2 u x + c_{1}, y = - 2 u x + c_{1}

Solution steps

\frac{d y}{d x} y = u

Solve separable ODE:

y = 2 u x + c_{1}, y = - 2 u x + c_{1}

y = 2 u x + c_{1}, y = - 2 u x + c_{1}

\frac{d y}{d t} = 3 y, y (6) = 1

y^{^{'}} = - 2 y

- \frac{( - y ^{^{'}} + 72 )}{24} + y + \frac{y ^{^{'}}}{48} = 0

\frac{d y}{d x} = (- \frac{2 y ^{2}}{x ^{2}})

y \cdot y^{^{'}} = cos (t)

What is the solution for (dy)/(dx)y=sqrt(u),u=x^2+2 ?
The solution for (dy)/(dx)y=sqrt(u),u=x^2+2 is y=sqrt(2\sqrt{u)x+c_{1}},y=-sqrt(2\sqrt{u)x+c_{1}}