What is the solution for -((-y^'+72))/(24)+y+(y^')/(48)=0 ?

The solution for -((-y^'+72))/(24)+y+(y^')/(48)=0 is y=-e^{-16t-c_{1}}+3

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-((-y^'+72))/(24)+y+(y^')/(48)=0

- \frac{( - y ^{^{'}} + 72 )}{24} + y + \frac{y ^{^{'}}}{48} = 0

y = - e^{- 16 t - c_{1}} + 3

Solution steps

- \frac{( - y ^{'} ( t ) + 72 )}{24} + y + \frac{y ^{'} ( t )}{48} = 0

Solve separable ODE:

y = - e^{- 16 t - c_{1}} + 3

y = - e^{- 16 t - c_{1}} + 3

\frac{d y}{d x} = (- \frac{2 y ^{2}}{x ^{2}})

y \cdot y^{^{'}} = cos (t)

\frac{d y}{d t} + \frac{15}{200} y = 0

x (2 x^{2} - 1)^{2} d x + y^{2} sin (y^{3}) d y = 0

y^{^{'}} - \frac{4}{x} y = \frac{5}{x}

What is the solution for -((-y^'+72))/(24)+y+(y^')/(48)=0 ?
The solution for -((-y^'+72))/(24)+y+(y^')/(48)=0 is y=-e^{-16t-c_{1}}+3